The Re-Volt Network
The following graph shows how the cumulative product decreases as more terms are added to the sequence. The product of the sequence is exactly
To "prepare paper" for the expression , we must first define the product's range and then calculate its value. Assuming the sequence continues until the numerator reaches the denominator's value ( ), the product is: (2/32)(3/32)(4/32)(5/32)(6/32)(7/32)(8/32)(9/32...
We can rewrite the product of these 31 fractions as a single expression using factorials: The following graph shows how the cumulative product